Col 3The error associated with the variance estimation.
Details
Given N equally spaced samples with averaging time tau=n∗tau0, where n is an integer such that 1<=n<=N/2. Therefore, n is able to be selected from n∣n<floor(log2(N))
Then, a sampling of m=⌊nN−1⌋−1 samples exist. The tau-overlap estimator is given by: